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Saturday, February 28, 2015

LINEAR ALGEBRA
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For details see post on 26-Feb-2015 at 6:00 am.
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Determine whether b is in the column space of A. If it is, then write b as a linear combination of the column vectors of A. (Use v1, v2, and v3, respectively, for the three columns. If not possible, enter IMPOSSIBLE.)
A = [(1,3,0);(-1,1,0);(2,0,1)]
b= [(2,3,-4)]
A=
UVWB=X=
1-122P
3103Q
001-4R
AX=B………X=A INVERSE *B
A INVERSE =
0.250.25-0.5
-0.750.251.5
001
X= A INVERSE * B =
3.25
-6.75
-4
HENCE B IS IN COLUMN SPACE OF A
B = 3.25*U-6.75*V-4*W……………….ANSWER

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