MATRICES
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A=	[A1,A2,A3]
A1=	A2=	A3=		X=		B=
C	G	L		2		B1
D	H	M	*	1	=	B2
E	J	N		6		B3
F	K	P				B4
a)…TO CHECK VECTOR B IS IN SPAN OF A[A1,A2,A3]
A*X = B
THAT IS …
2A1+A2+6A3=B
THIS CLEARLY IMPLIES THAT VECTOR B CAN BE WRITTEN
AS A LINEAR COMBINATION OF A1,A2,A3
HENCE B IS IN THE SPAN OF A[A1,A2,A3]
PROVED