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Friday, November 10, 2006

QUESTIONS - INEQUALITIES & POLYNOMIALS

QUESTIONS - ANSWERS - INEQUALITIES
Anonymous has left a new comment on your post "Questions - Continuous Compounding":

Help please! Solve the following equation, then write solution in set notation. |x+10|<5



Posted by Anonymous to Maths,management,counselling at 8:57 AM

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ANSWER:
|x+10|<5
case 1...
x+10>0....x>-10
|x+10|= x+10<5
x<5-10= -5
hence solution set is
(-10,-5)
case 2...
x+10<0....x<-10
|x+10|=-(x+10)=-x-10<5
-x<15
x>-15
hence solution set is
(-15,-10)


QUESTION - POLYNOMIALS

Anonymous has left a new comment on your post "Questions - Continuous Compounding":

OOps forgot one more. For the polynomial f(x)=-2x^3+3, which statement is true? a)as x goes to minus infinity, f(x) is increasing; and as x goes to infinity, f(x) is decreasing. b)as x goes to minus infinity, f(x) is decreasing; and as x goes to infinity, f(x) is decreasing c) neither Thank you!

ANSWER
f(x)=-2x^3+3
as x tends to plus infinity..x^3 tends to plus infinity and -x^3 tends to - infinity
hence f(x) tends to -infinity as x tend to infinity.That is f(x) is decreasing
similarly as x tend to - infinity , f(x) tends to plus infinity.That is increasing.

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