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Thursday, November 09, 2006

QUESTIONS - POLYNOMIALS

QUESTIONS - ANONYMOUS - POLYNOMIALS
Anonymous has left a new comment on your post "PANCHATANTRA – 6.PROJECT MANAGEMENT":

Hello again, sir. I'm in need of your help. Determine the value of x where the following polynomial function touches the x-axis and tell whether it crosses the axis or is tangent to it. f(x)=-2x^3 Thank you.
f(x) = -2x^3 = 0 at x=0
f'(x) = -6x^2 = 0 at x =0
f"(x)= -12x = 0 at x= 0
f"'(x) = -12 = -12 at x=0
hence the curve crosses x axis at x=0 where y is also zero.
since its slope is zero at x=0, it means the slope of its tangent at x=0 is zero.
further it passes through x=0,y=0.hence
y-0 = 0*(x-0)=0 is the eqn. of the tangent at that point.
that is x axis is tangent to the curve at x=y=0.

2 Comments:

Anonymous Anonymous said...

If you have the time to lend some help, I'd be grateful.

1) Determine the domain of the following rational function. Give the answer in set notation and in interval notation.
f(x) = 15 / (x + 10)


2) What are the vertical asymptotes of the following rational function?
f(x) = (x+3) / (x2 + x –20)

Thanks so much.

8:01 PM

 
Anonymous Anonymous said...

on that last problem, for #2 it should be x^2+x-20 not x2+x-20

Sorry for any confusion.

8:03 PM

 

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