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Wednesday, December 20, 2006

QUESTIONS - CDOG - MATRICES

QUESTIONS - ANSWERS - CDOG - MATRICES


cdog has left a new comment on your post "MATHS - 8 - MATHS FOR ALL - PROBLEM SOLVING TECHNI...":

Solve the matrix equation {[3,a][c,d]}={[b,a-c][b+d,4a]} same thing as Matrix 3 a = Matrix b a-c c d b+d 4a Thanks again!

LHS =
3,A
C,D
RHS =
B,A-C
B+D,4A
EQUATING CORRESPONDING ELEMENTS..
B=3……………….1
A-C=A……C=0………………2
B+D=C=0…..FROM EQN.2…HENCE
B+D=….FROM. EQN.1.
3+D=0
D=-3…………………………………3
4A=D = -3 FROM EQN.3.
A = -3/4……………………………..4
HENCE
A=-3/4
B=3
C=0
D=-3

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